2 months agoOne detail, it is technically not true to say that the position eigenstates form basis vectors in the Hilbert space. This is because the position operator is unbounded and discontinuous in the operator topology induced by the bra-ket inner product. Thus, it has no eigenvectors at all! However, if we extend the Hilbert space of wavefunctions to include distributions, then the position operator will have eigenvectors in this "rigged" Hibert space, which in the position representation are Dirac-delta distributions. I think this is important to point out because this state of affairs is typically assumed in quantum mechanics courses, but it is often a detail not discussed with enough attention. Even though it comes up quite often in quantum field theory when you want to discuss, e.g., field operators.
3 months agoThat's beautiful design and visualization for a complex topic like Quantum Mechanics 😮👏. May I know what tools do you use to create the slides?
