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5 months ago
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Posted On: March 4th 2026, 11:11 pm
Comments (130)
ericguenov 2 months ago

ericguenov

Why is -30 wrong, you have to find whats under the square root. With x=-30, it gives 25 (positive). The square root limits the domain to -x-5 >= 0 (x =< -5), not x >= 0

karamsafi11 2 months ago

karamsafi11

X=-30,20

white.wolve22 2 months ago

white.wolve22

The root itself is over -(-30)-5 so it's fine. As it is a possitive number after the equation

giorgosath0_o 2 months ago

giorgosath0_o

Let me guess x=-30?

alih_51214 2 months ago

alih_51214

It can be simplified as sqrt[-1] × sqrt[x+5]=-5. From now, its easy. sqrt[x+5]=-5/i. X+5=(-5/i)^2. X+5=25/-1. X+5=-25. X=-25-5. X=-30.

melle_cel 2 months ago

melle_cel

It’s wrong but for the wrong reason, when replacing x you don’t care what is infront of it -(x). So then it would be -(-30) which is just 30, 30-5 is 25 and the square root of 25 is 5 and that’s where it’s wrong 5≠-5

jafar2000jafar 2 months ago

jafar2000jafar

No I start with you can't have negative from root

the_f1l1p 2 months ago

the_f1l1p

X=-30, but X also equalss20, when canceling the square root and square of something, you gotta put it in these brackets: ||..|-x-5|=25, |-20-5|=25, |-25|=25, 25=25.

conrrado_presty 3 months ago

conrrado_presty

Si tiene solución

_borkich 3 months ago

_borkich

Sqrt cannot be less than 0 idk what kind of math y'all be studying

_paulluss_ 3 months ago
whostolemyksubis 3 months ago

whostolemyksubis

i love all these nerds in the comments

yaakoub___am 3 months ago

yaakoub___am

When you square the root the number inside the root comes out with an absolute value so it will be x+5

johnwhitefoot123 4 months ago

johnwhitefoot123

No -30 is correct because --30-5 = 25

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